{"id":35,"date":"2010-04-15T20:48:52","date_gmt":"2010-04-15T18:48:52","guid":{"rendered":"http:\/\/technocktail.info\/?p=35"},"modified":"2017-07-20T01:39:02","modified_gmt":"2017-07-19T23:39:02","slug":"work-and-torque-solution","status":"publish","type":"post","link":"http:\/\/technocktail.info\/?p=35","title":{"rendered":"Work and Torque (Solution)"},"content":{"rendered":"<p><strong><em>THIS IS A REDUNDANT POST \ud83d\ude00 \u00a0AND THE ORIGINAL POST IN MY Quantity System Blog<\/em><\/strong><\/p>\n<p><a href=\"http:\/\/quantitysystem.wordpress.com\/2010\/04\/15\/work-and-torque-solution\/\">http:\/\/quantitysystem.wordpress.com\/2010\/04\/15\/work-and-torque-solution\/<\/a><\/p>\n<p>&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8211;<\/p>\n<p>I am really sorry<\/p>\n<p>I didn&#8217;t notice that I haven&#8217;t posted how did I solve the\u00a0dilemma\u00a0of Torque and Work Problem<\/p>\n<p>however the solution was there in my discussion of quantity System\u00a0<a href=\"http:\/\/quantitysystem.codeplex.com\/Thread\/View.aspx?ThreadId=23672\">http:\/\/quantitysystem.codeplex.com\/Thread\/View.aspx?ThreadId=23672<\/a><\/p>\n<p>and also on this post of my personal blog \u00a0<a href=\"http:\/\/blog.lostparticles.net\/?p=28\">http:\/\/blog.lostparticles.net\/?p=28<\/a><\/p>\n<h1>Problem Core: Length<\/h1>\n<p>Simply I defined TWO Length Types<\/p>\n<h2>Normal Length (NL)<\/h2>\n<p>This is the normal length that we refer to it in our daily life<\/p>\n<h2>Radial Length (RL)<\/h2>\n<p>This is the radius length that have an origin point in center of circle<\/p>\n<h2>Quantities<\/h2>\n<p>Work: \u00a0 \u00a0 \u00a0 Force * Normal Length<\/p>\n<p>Torque: \u00a0 Force * Radial Length<\/p>\n<p>Angle: \u00a0 \u00a0 \u00a0Normal Length \/ Radial Length<\/p>\n<p>In quantity system I made the L dimension as NL+RL<\/p>\n<p>CAN YOU SEE ANGLE<\/p>\n<p>I made it explicitly a quantity that is NOT dimensionless<\/p>\n<p>and THIS SOLVED ALL my problems of this Problem<\/p>\n<p>I won&#8217;t argue much let us test \ud83d\ude42<\/p>\n<p>Torque * Angle = Work<\/p>\n<p>F*RL * (NL\/RL) = \u00a0F * NL \u00a0 \u00a0&lt;== see what I mean<\/p>\n<p>Torque * Angular Speed = Power<\/p>\n<p>F*RL * (NL\/RL*T) = F*NL\/T \u00a0 &lt;== where T is the time.<\/p>\n<p>so you may wonder about Angle and Solid Angle<\/p>\n<p>in SI they are all dimensionless \u00a0but in Quantity System YOU CAN&#8217;T consider them like this<\/p>\n<p>(By the way I&#8217;ve break the checking for these two quantities to be\u00a0summable with dimensionless numbers &#8211; just to keep the\u00a0fundamentals\u00a0as it is although I am not convinced\u00a0and I may remove it in future but damn it I need support from any physics guy)<\/p>\n<p>ANGLE : \u00a0NL\/RL<\/p>\n<p>Solid Angle: \u00a0NL^2\/RL^2 \u00a0 because its area over area<\/p>\n<p>Frequency = \u00a01\/T<\/p>\n<p>Angular Velocity = (NL\/RL)\/T<\/p>\n<p>do you remember the conversion between RPM to frequency<\/p>\n<p>RPM (Revolution Per Minute) is a Angle \/ Time<\/p>\n<p>lets test the law<\/p>\n<p>Omega \u00a0= 2*pi*frequency<\/p>\n<p>pi: radian value which is \u00a0NL\/RL<\/p>\n<p>Omega = (NL\/RL) * 1\/T = (NL\/RL)\/T \u00a0 which \u00a0angular velocity<\/p>\n<h1>Discoveries<\/h1>\n<h2>PI value<\/h2>\n<p><a href=\"http:\/\/en.wikipedia.org\/wiki\/Pi\">PI<\/a> is ratio of any\u00a0<a title=\"Circle\" href=\"http:\/\/en.wikipedia.org\/wiki\/Circle\">circle<\/a>&#8216;s circumference to its diameter \u00a0 \u00a0WHICH MEANS \u00a0(NL\/RL)<\/p>\n<p>this is the same value as the ratio of a circle&#8217;s area to the square of its radius \u00a0 \u00a0 WHICH MEANS \u00a0(NL^2\/RL^2)<\/p>\n<p>which corresponds to radian unit and stradian unit for angle and solid angle quantities.<\/p>\n<h2>Reynolds Number<\/h2>\n<p>I am not holding back (\u00a0<a href=\"http:\/\/en.wikipedia.org\/wiki\/Reynolds_number\">Reynolds number<\/a> is a dimensionless number that measure inertial forces to viscous forces)<\/p>\n<p>WHY we always differentiating between Flow in Pipes and Flow on Flat plate<\/p>\n<p>let&#8217;s see with normal length in quantity system<\/p>\n<div id=\"_mcePaste\">Qs&gt; rho = 3[Density]<\/div>\n<div id=\"_mcePaste\">Density: 3 &lt;kg\/m^3&gt;<\/div>\n<div id=\"_mcePaste\">Qs&gt; v=0.5&lt;m\/s&gt;<\/div>\n<div id=\"_mcePaste\">Speed: 0.5 &lt;m\/s&gt;<\/div>\n<div id=\"_mcePaste\">Qs&gt; l=4&lt;m&gt;<\/div>\n<div id=\"_mcePaste\">Length: 4 m<\/div>\n<div id=\"_mcePaste\">Qs&gt; mue = 2&lt;Pa.s&gt;<\/div>\n<div id=\"_mcePaste\">Viscosity: 2 &lt;Pa.s&gt;<\/div>\n<div id=\"_mcePaste\">Qs&gt; rho*v*l\/mue<\/div>\n<div id=\"_mcePaste\">DimensionlessQuantity: 3 &lt;kg\/m.s^2.Pa&gt;<\/div>\n<p>it shows it is a dimensionless quantity<\/p>\n<p>ok let us force my theory about flow in pipes<\/p>\n<p>the pipe have a diameter \u00a0and Reynolds number is calculated by rho*v*DIAMETER\/viscosity<\/p>\n<p>so let me add d as a diameter and solve again<\/p>\n<p>Qs&gt;\u00a0d=0.5&lt;m!&gt;<\/p>\n<p>RadiusLength: 0.5 m<\/p>\n<p>Qs&gt; rho*v*d\/mue<\/p>\n<p>DerivedQuantity: 0.375 &lt;kg\/m.s^2.Pa&gt;<\/p>\n<p>NOTE: Adding &#8216;!&#8217; after the length unit will mark the quantity as Radial Length quantity.<\/p>\n<p>ERROR \u00a0it shouldn&#8217;t be DerivedQuantity at all it should be Dimensionlesss<\/p>\n<p>so there is another term that should be fixed. Do you know which term ???<\/p>\n<p>lets try the velocity \u00a0with\u00a0vr=0.5&lt;m!\/s&gt;<\/p>\n<p>Qs&gt; vr=0.5&lt;m!\/s&gt;<\/p>\n<p>DerivedQuantity: 0.5 &lt;m\/s&gt;<\/p>\n<p>Qs&gt; rho*vr*d\/mue<\/p>\n<p>DerivedQuantity: 0.375 &lt;kg\/m.s^2.Pa&gt;<\/p>\n<p>ALSO ERROR<\/p>\n<p>ok let us try the density<\/p>\n<p>Qs&gt;\u00a0rhor = 3&lt;kg\/m!^3&gt;<\/p>\n<p>DerivedQuantity: 3 &lt;kg\/m^3&gt;<\/p>\n<p>Qs&gt; rhor*v*d\/mue<\/p>\n<p>SolidAngle: 0.375 &lt;kg\/m.s^2.Pa&gt;<\/p>\n<p>CAN YOU SEE THE SOLID ANGLE Quantity<\/p>\n<p>do you remember the above argue about Solid Angle is dimensionless number<\/p>\n<p>can I pretend now that reynolds number for pipes is CORRECT ???<\/p>\n<p>the new density which is kg\/m!^3<\/p>\n<p>This is driving me nuts<\/p>\n<h2><\/h2>\n<h2>Pump Affinity Laws<\/h2>\n<p>Also \u00a0pump equations led to the same\u00a0SolidAngle\u00a0Quantity not\u00a0DimensionLess\u00a0one<\/p>\n<h1>Epilogue<\/h1>\n<p>I&#8217;ve said what I&#8217;ve discovered till now about this problem I hope that may be someday someone explain to me or convince me that Angle is really a Dimensionless number \u00a0 after all of this and that my assumption about Torque and Work is Wrong.<\/p>\n<p>Qs&gt; rho = 3[Density]Density: 3 &lt;kg\/m^3&gt;Qs&gt; v=0.5&lt;m\/s&gt;Speed: 0.5 &lt;m\/s&gt;Qs&gt; l=4&lt;m&gt;Length: 4 mQs&gt; mue = 2&lt;Pa.s&gt;Viscosity: 2 &lt;Pa.s&gt;Qs&gt; rho*v*l\/mueDimensionlessQuantity: 3 &lt;kg\/m.s^2.Pa&gt;<\/p>\n","protected":false},"excerpt":{"rendered":"<p>THIS IS A REDUNDANT POST \ud83d\ude00 \u00a0AND THE ORIGINAL POST IN MY Quantity System Blog http:\/\/quantitysystem.wordpress.com\/2010\/04\/15\/work-and-torque-solution\/ &#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8211; I am really sorry I didn&#8217;t notice that I haven&#8217;t posted how did I solve the\u00a0dilemma\u00a0of Torque and Work Problem however the solution was there in my discussion of quantity System\u00a0http:\/\/quantitysystem.codeplex.com\/Thread\/View.aspx?ThreadId=23672 and also on this post of my [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1],"tags":[],"_links":{"self":[{"href":"http:\/\/technocktail.info\/index.php?rest_route=\/wp\/v2\/posts\/35"}],"collection":[{"href":"http:\/\/technocktail.info\/index.php?rest_route=\/wp\/v2\/posts"}],"about":[{"href":"http:\/\/technocktail.info\/index.php?rest_route=\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"http:\/\/technocktail.info\/index.php?rest_route=\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"http:\/\/technocktail.info\/index.php?rest_route=%2Fwp%2Fv2%2Fcomments&post=35"}],"version-history":[{"count":7,"href":"http:\/\/technocktail.info\/index.php?rest_route=\/wp\/v2\/posts\/35\/revisions"}],"predecessor-version":[{"id":52,"href":"http:\/\/technocktail.info\/index.php?rest_route=\/wp\/v2\/posts\/35\/revisions\/52"}],"wp:attachment":[{"href":"http:\/\/technocktail.info\/index.php?rest_route=%2Fwp%2Fv2%2Fmedia&parent=35"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"http:\/\/technocktail.info\/index.php?rest_route=%2Fwp%2Fv2%2Fcategories&post=35"},{"taxonomy":"post_tag","embeddable":true,"href":"http:\/\/technocktail.info\/index.php?rest_route=%2Fwp%2Fv2%2Ftags&post=35"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}